Self-Referencing Lambda Functions in Python

Would this work? Can a lambda function reference itself in Python?

fibonacci = lambda n: n if n <= 1 else fibonacci(n - 1) + fibonacci(n - 2)
assert fibonacci(5) == 5
assert fibonacci(6) == 8

Yes, it works!

In Python, a lambda function can indeed reference itself. In this example, the lambda function fibonacci is able to call itself within its own definition. This is possible because the fibonacci variable is available in the scope at the time the lambda is evaluated.

Here is a simple example to illustrate this concept:

fun = lambda: x
x = 3
assert fun() == 3

In this example, the lambda function fun references the variable x, which is defined after the lambda. When fun() is called, it correctly returns the value of x. This shows how lambdas can reference variables within their scope, even if those variables are defined later.